15x^2-28x-4=0

Solution for 15x^2-28x-4=0 equation:

Simplifying
15x2 + -28x + -4 = 0

Reorder the terms:
-4 + -28x + 15x2 = 0

Solving
-4 + -28x + 15x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-2 + -15x)(2 + -1x) = 0

Subproblem 1
Set the factor '(-2 + -15x)' equal to zero and attempt to solve:

Simplifying
-2 + -15x = 0

Solving
-2 + -15x = 0

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -15x = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -15x = 0 + 2
-15x = 0 + 2

Combine like terms: 0 + 2 = 2
-15x = 2

Divide each side by '-15'.
x = -0.1333333333

Simplifying
x = -0.1333333333
Subproblem 2
Set the factor '(2 + -1x)' equal to zero and attempt to solve:

Simplifying
2 + -1x = 0

Solving
2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = 0 + -2
-1x = 0 + -2

Combine like terms: 0 + -2 = -2
-1x = -2

Divide each side by '-1'.
x = 2

Simplifying
x = 2
Solution
x = {-0.1333333333, 2}